我想请教一下100分求D dnf无时装改天空4...

D NF一套便宜的时装多少钱,_百度知道
D NF一套便宜的时装多少钱,
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出门在外也不愁冷月魅影lymy
很好听 不过感觉列适合小潜潜
冷月魅影lymy
简捷明了 又有深意 比较支持
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display: 'inlay-fix'求大侠帮忙修改一下这个des算法,用c或c++~~~_百度知道
求大侠帮忙修改一下这个des算法,用c或c++~~~
有没有能帮忙修改一下的.com/question/!,不需要填充操作,里面的像ByteToBit类似的函数也看不太懂.html" target="_blank">http.baidu。3。调试运行通过的,再加100分。2。我在做这3个条件的过程中<a href="http!同时也欢迎各位大侠能指导一下,所以不需要加密解密文件这么复杂。直接内置或者键盘输入都行,最好内置.明文和密钥都为已知的64位2进制数,当然初始密钥也是已知的2进制数,不需要字符或者别的东西,只要把已知的2进制数加密成另一个2进制数就行了,要求修改成以下条件,主要问题是第2项。要修改成这样的原因是为了生成伪随机数:1!,我的qq:://zhidao,密钥和密文不需要以文件形式为输入输出.com/question/.明文。所以请教一下各位大侠.baidu://zhidao.不需要解密操作.html算法是这个网址上的算法
这个步骤我不需要,作用是以文件为输入再以文件为输出,连解密都不用回答一或许没有明白我的意思,差不多就这样,我只要一个64位的字符或者整形数组把2进制数明文放进去运算成密文就行了。有心的最好把main函数也写一下,这里的加密解密函数里的参数是指针类型的
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#include &*S4*/long MOVE_TIMES[16] = {1,0,6,36,1,14; cnt &lt,16,3;
copyRight[41]=a[52],&#47,2,50,
{1,1;*S5*/
copyRight[34]=a[36],7, ElemType right[32]){
ElemType temp[32],8; 8,5;*化为2进制*&#47,0;
DES_Swap(plainBits,10,0,
{4;stdio,19;
/*16轮迭代*&#47,13;x++)
d[1+x]=b[58+x],48,5,0;long PC_1[56] = {56,8,
0,产生16个子密钥*&#47,2,15,1;*对左移次数的规定*&#47,10,14,1;
for(cnt = 0,6,1,13; &#47,1; cnt++){
temp[cnt] = data[E_Table[cnt]],40,12,0,9,50.h&quot,1,0; 16, ElemType subKeys[16][48],long DES_IP_1_Transform(ElemType data[64]){
for(cnt = 0;48; 48; 64;&
for(cnt = 0;
copyRight[38]=a[44],1,1,1;*扩充置换表E*&#47,1,
{13,11,29; count,0,40,0,3}},11;k&lt,45,6;*S8*/
memcpy(long IP_Table[64] = {
57,8,53,0,10,3!=15){
DES_Swap(a,3,0,0,12,data,42;
data[cur2+2] = (output&0X02)&gt,11;
return 0,30,2,20,time);*S盒*&#47,temp,
copyRight[33]=a[35],2,0,33,26;
&#47,8,28; cnt++){
temp[cnt] = data[IP_1_Table[cnt]],
{14,10;3) + (data[cur1+2]&lt,13,20,1,39,11,11,1; }
return 0,15,1, 4,0,plainBits,data+28+time,0,11},6,4, 0},
36,53; cout&lt,1,0,0,1;&#47,41,
38,18,12,10,13,0;
DES_XOR(copyRight,
for(cnt = 0,0,
15,0,2,0,8},7; long temp[48],
DES_P_Transform(copyRight),1,
6,bkey),9;Bit64ToChar8(plainBits,6;*扩展置换*&#47,11;
&#47, 5,49,31; cnt++){&#47,0;*P置换*&#47,6,1,57,11;DES_IP_Transform(a),14, 0,copyRight,14,2,1;*密钥置换1*&#47,9,19,0;*异或*&#47,2},15,
{0,13,0;*将右半部分与子密钥进行异或操作*/
DES_PC1_Transform(key,28,5,13}},15,10,10,5,11,5,10,11,18; cnt &lt,long bkey[64]){ long copyRight[48],1,7,11,
13;i&t&lt,2,6;2,11,5; cnt &lt,bkey),14;*PC1置换*&#47,36,1,
0,8,row,15;
memcpy(data+56-time,27,temp+time,4; cnt &lt,11,1;*S7*&#47,30;
ElemType temp[48],0;&#47,28-time),9;*逆初始置换表IP^-1*&#47!= 15){&#47,8},2,22,1;i&lt,
{1,14}},7,57#include &quot,0,temp,44,17,
DES_PC2_Transform(temp,64),0,28,11,2,0,12;*保存将要循环移动到右边的位*&#47,
62,8;6,1,55;
return 0,3,0,ElemType subKeys[16][48]){
ElemType temp[56],14,13; &#47,1,32);
ElemType temp[32],MOVE_TIMES[0]);*IP置换*/
output = S[cnt][line][row];
if(cnt,1, 1,8,1,0,12,11; long b[64]={
0,7,0,15,25,0;&#47,5,40,1; return 0;long DES_Swap(ElemType left[32];
return 0,long count){long DES_EncryptBlock(ElemType plainBits[64],
0;&#47,27,10,9,0,1,12,47,1;endl,0,24;*将右半部分进行扩展置换,15;*S1*&#47,0;&lt,52,12,3,12,2,0,
return 0,1,0},8,1,11,2,25,55,14;*逆初始置换(IP^1置换)*&#47,6},
DES_ROL(temp,7},14,15,8,4,9,4,temp,
1,30,7,subkey[cnt],9,temp),1;
long cur1,9; DES_jiami(b;
memcpy(data+28-time,15,3,39,1,
0,1,0;&#47, 8,
&#47,16,1,10,45,27,3,63,time),12}};*初始置换表IP*/ 16,54,14,11,
{1,2,15,10;
return 0,0,8,2,1;
59;long DES_E_Transform(ElemType data[48]){
long cnt,1,10;endl,1;
copyRight[43]=a[56];
copyRight[32]=a[32],0; c[0]=1,9,15,32,
DES_P_Transform(copyRight),2,1,11,28,1;*生成子密钥*&#47,9,12,5,5,7;}long DES_PC2_Transform(ElemType key[56],
1,17,12,0,12;
return 0,7;&lt,48),7,13,
{0,0;&lt,5;&#47,15,1,5,12,1; cnt++){
memcpy(copyRight,28-time),51,2;
return 0,1,20,3; cnt++){
R[cnt] ^= L[cnt],16,46,21;
&#47,9,2,34,1,1,0,49,12,0, ElemType L[48] ,43,5,
60,1,6,33;
copyRight[37]=a[43];i++)
subKeys[cnt][i]=temp1[i],46,2;
long line,0,0,6,32),7;
long cnt,12,7;i++)
subKeys[cnt][i]=temp[i],4,15,1,12, ElemType tempbts[56]){
long cnt,1, 3,0,0,10;t=c[7]+c[6]*10+c[5]*100+c[4]*1000+c[3]*10000+c[2]*100000+c[1]*1000000+c[0]*, long time){
ElemType temp[56],
33,21,19,9}},6};
&#47,29,3},12;
data[cur2+1] = (output&0X04)&gt,10,1,5,25,24,
0,14,7; c[7]=1;*S6*&#47,1,10,0;stdlib,0;
DES_SBOX(copyRight),1;c[j],6,8,0,9},1,12,11,58;
#define PLAIN_FILE_OPEN_ERROR -1#define KEY_FILE_OPEN_ERROR -2#define CIPHER_FILE_OPEN_ERROR -3#define OK 1 typedef long ElemType,51,16,4,10,0,6},
8,48,52,9,5,1,43,
&#47,53;&gt,12,4,12,3;*置换选择1*/
DES_IP_1_Transform(plainBits),22,16;long P_Table[32] = {15;
&#47,14,15,4,2,1; cnt &lt,10,21,23;
}&#47,58,11,8,14;
memcpy(data,1,15},a+32),4,16,d[8],
0,0,30,11,temp,13;
data[cur2+3] = output&0x01,14,2,8,2,7,20; d[0]=1,2,2,32);*置换选择2*&#47,4,2,plainBits+32,23,13.h&quot,1;
copyRight[39]=a[47],从32位扩展到48位*/
copyRight[47]=a[63],1,
61,12,0; 56,0,3,41,15,11; } for( x=0,
{7,1;long DES_SBOX(ElemType data[48]){
long cnt,7,2,1;
return 0,11,13,
{9,22,&lt,7,19;j&lt,6,0,15,0,3,13,1,45,15,9,25,45,6},11,6,11,7;} long DES_P_Transform(ElemType data[32]){8,13;long DES_IP_Transform(ElemType data[64]){
32,4,56,64),13; p=d[7]+d[6]*2+d[5]*4+d[4]*8+d[3]*16+d[2]*32+d[1]*64+d[0]*128;*计算在S盒中的行与列*&#47,13,14,12,5;long S[8][4][16] =&#47,13}},6,9; cnt &lt,0,15,5;#include &quot,0;using namespace std,
ElemType temp[64],6,8,3,
&#47,5,4,8,left.h&quot,3;
line = (data[cur1]&{{{14;*16轮跌代,7,0,9,5,
1,0,1,1;&lt,7,1;}
&#47,14,2;j++){&#47,11}}},7,0,12,
{3,9,11, ElemType tempbts[48]){
long cnt,0,8}; cnt &lt,9;
row = (data[cur1+1]&lt,1,23; DES_MakeSubKeys(bkey,1},13,9,25; cnt++){
tempbts[cnt] = key[PC_2[cnt]],0,10,9,0,1,1,2,9,1 };
copyRight[44]=a[57];&1;
DES_E_Transform(copyRight);x&lt,5,14,1,0,
0,8,10;#include & long a[64]={
copyRight[40]=a[48],
1,1,14,2;*交换*&#47,{4;
for(cnt = 0,3;&#47, ElemType cipherBlock[64]){
ElemType copyRight[48],35,35,23; 32,1,5,5,26,
25,1;/}long DES_jiami(long a[64];
for(cnt = 0,cur2;
copyRight[46]=a[62];iostream&gt,6;long DES_MakeSubKeys(ElemType key[64],
23,64),13, 2; DES_jiami(a,1,0,27,0;}
&#47,49; cnt++){
tempbts[cnt] = key[PC_1[cnt]],4,17,0,输出32位结果*&#47,48); long c[8],14,34,3,30,8,9,1,1,1,2,8,1,0,61;
copyRight[42]=a[53];}/*后28位移动*&#47, d[7]=1,1};}
&#47,2;*前28位移动*/ long subkey[16][48],29,15,0,44,4},12,10},6;
/&lt,4, 6,1;/
DES_XOR(plainBits,0,11;
memcpy(temp,10,0; cnt++){
temp[cnt] = data[P_Table[cnt]]; 48;*初始置换(IP置换)*&#47,35,13,1,15,12,1,11,
18,1,0,24},
1,0;&#47,14,38,14,1;}/
&#47,1,14;} &#47,13,9,3,2,1,52; 64,5,10,50,1,3; for(long x=0;
memcpy(1) + data[cur1+4],0,6;&lt,3,2,1,61,19;long PC_2[48] = {13,14},14,14,1,4;
&#47,62,11,12}},31; cnt++){
cur1 = cnt*6,2,32),12,
20,8,2,9;&gt,3,59,
memcpy(data,9},6,11,54,17,1,1,
11,51,14,7},8;1) + data[cur1+5],5,15,7;
data[cur2] = (output&0X08)&gt,5,13,4;
return 0,8,6,8;
DES_E_Transform(copyRight),5,12,32,37;
return 0;*加密单个分组*&#47,
58,10,8,24,0;
for(cnt = 0,
50,1,0,5,13,1;}
long DES_ROL(ElemType data[56];
for(cnt = 0; /*S盒置换*/}
/#include &quot,1,29,8,42;32,4,24},0,26,15,54,0;
memcpy(data+28,48,15,12,2,0,12,6,46; cnt++){
temp[cnt] = data[IP_Table[cnt]],15,5,13;
DES_IP_Transform(plainBits),5; cnt &lt,3,52,1,0,8; t=c[7]+c[6]*2+c[5]*4+c[4]*8+c[3]*16+c[2]*32+c[1]*64+c[0]*128,5;
for(long i=0,
&#47,11,0,42,37,0,data+2)
+ (data[cur1+3]&lt,3,44,14,1,22,46,
9,20,p,14,7,0,0,8,49,15,6,9,9,0,8; cnt &lt,1,0,5; long t,6,17,1,7;for(long cnt = 0,12;*置换函数P*&#47,24,4,
copyRight[35]=a[39],7,13,14,29,11,1;*最终完成左右部的交换*&#47,7;long IP_1_Table[64] = {39;memory,3;
ElemType temp[64],7,2,29;}long main(){ long bkey[64]={
&#47,2,12,6,4;&lt,6,8},20,3;
cur2 = cnt&lt,time),4;
cout&lt,3;*将明文左半部分与右半部分进行异或*&#47,13;
1,5;*异或结果进入S盒,15,15},5,temp,2;*S3*/&#47,1};&lt,4,1 };
DES_XOR(copyRight,
{10;*IP逆置换*/
&#47,13,15,48);*S2*/
return 0,6;
copyRight[45]=a[61],4,12; 16,
18,46,0,28,
{6,8,54,2,11,43,38,5,60,plainBits+32),4,1,1,11,4,8,2,14,3,6,7,7},22;long E_Table[48] = {31,4,10,27,9,0,9,subkey),1,2,
{3.h&quot,cipherBlock),32),31},temp1),
56,0,26,41;
{{13,0,14,0,23,8,14,data+28,0,3,48;
memcpy(data,13,
4;long DES_PC1_Transform(ElemType key[64]; cout&
for(cnt = 0,1,1,1,{15, 7,1,10,1,0,9;
{{15,0;long DES_XOR(ElemType R[48],1,0,7;&lt,0,
DES_SBOX(copyRight),7,13,30,4,16;&#47,15,15,2},15,22,3,21,2,0,5;
memcpy(left,copyR
copyRight[36]=a[40];
for(long i=0,32),
DES_XOR(a,
34,7;endl,2,6,10; cout&lt,
{13,4,0,6,43,3;
{{12,7,1,3,11,60,8,1,15,1,10,6; cnt++){
for(long k=0,32),1,55,4;
&#47,0,0;/3;
memcpy(temp+time,13;
memcpy(data,0 },14,12,0,10,10,32,1,18,12,18;x&lt,7,5,19,10,
33,time),28,1,5,10,
0,0,44,1; ElemType temp1[48],temp,10;
for(cnt = 0,10,9;
DES_IP_1_Transform(a),
0,1; for(long j=0,28,0;6;
long temp[48]; cnt &x++)
c[1+x]=a[58+x],47;48;p& memcpy(cipherBk++)
copyRight[k]=a[32+k],36,3,4,21,0,1,
1,14;return 0,26,
0,31,4,5},9; cnt &lt,0,1,41,6,1,9,3,1,
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int &cipherlen, int datalen,char *cipherText) 这个就是加密int DES_Decrypt(char *cipherText,char *keyStr根本就不需要改int DES_Encrypt(char *plainText,char *keyStr
要改的是:(1)首先生成明文的64bit的随机数(2)由于加密函数的输入是字节类型的,那么在调入加密函数前利用bittobyte函数把明文转化成为8个字节就可以了。再把读写文件的函数和解密函数直接删掉就行了。
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出门在外也不愁请英语达人帮我翻译一下简历(100分求)_百度知道
请英语达人帮我翻译一下简历(100分求)
实施和确认.7-2005; 个人素质.1在XX通信研发中心R&D硬件组从事手机射频项目的研发和调试工作,适应能力强有很好的团队精神和协作精神,富有挑战和竞争意识,主要负责射频线路设计和调试,基站割接传输。 在校期间多次参加院校电子制作竞赛;&#6年下半年用Delphi编写的“光纤熔接机仿真训练系统”获全院唯一优秀毕业设计奖1996.September-1999.June No; 2003.19 Middle school (Qingdao)工作经历, ,96年就拥有个人电脑: 射频工程师:有很强的创造力,整改方案的提出, oscilloscope、协调能力,对SAW,硬件工程师,LNA等器件有丰富的调测经验:&#61618,接受新事物快,网络覆盖状况的评估分析。根据信道可用率救载频,勤奋。职业期望在学校系统的学习了通信原理,熟悉VB编程,包括接入失败、线路话务监听,有丰富的射频开发,良好的沟通.102003年7月毕业后加入XX分公司负责BSC和MSC的维护, spectrum analyzer,路测数据的分析.10-2009, network analyzer、能吃苦有很好的自学和解决问题能力,熟悉 IS95和CMDA2000标准.等射频设备能够熟练操作,对as signal generator,有责任感个人能力; 2005、掉话等事件的分析。&#61618、信号处理以及计算机网络等专业知识,精通软硬件,察看传输质量,救站,作为项目接口人带领队伍出色完成了A和B的CDMA项目的研发任务,模拟数字和高频电路: CET6级,拆LOAD数据
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RF engineers, coordination, and adaptable Have a good team spirit and team spirit, familiar with VB programming: CET6 was the only outstanding graduate hospital design award 1996, implementat 2003, signal processing and computer network expertise. &#61618, oscilloscope, LNA, &quot. While studying at the school has participated in the production of the institutions of el 2005, is responsible for RF circuit design and debug.10-2009, to see the quality of transmission line traffic monitoring, the base station transmission割接and save the station, the second half of 2003 prepared by DelphiLearning in the school system of communication theory.1 R & D Center in the XX communications hardware R & D project team of mobile phone RF R & D and testing, familiar with the IS95 and CMDA2000 standards, able to endure hardship Have a good self-learning and problem-solving skills, road test data analysis, good communication. and other radio frequency equipment to skilled operation: &#61618, 96 years have personal computers, demolition LOAD data, as a project team led by the excellent interface were A and B completed the task of CDMA R & D projects, sense of responsibility Personal capacity, such as the transfer device has extensive testing experience.19 Middle school (Qingdao) Work experience, hard-working: Have a strong creative and full of challenges and the sense of competition, network analyzer . Career aspirations, the proposed reform program .10 In July 2003 after graduating from XX branch is responsible for the maintenance of BSC and MSC, network coverage of the assessment of the situation analysis, has a wealth of RF development, spectrum analyzer.7-2005, including access to the failure of the analysis of events s POptical Fiber Fusion Splicer simulation training system&quot, as signal generator, hardware engineers, on the SAW, accept new things fast, proficient in hardware and software. September-1999,. June No. Can be used in accordance with the rate of channel carri &#61618, analog-to-digital and high-frequency circuits
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really thanks
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In the school system of communication principle, the simulation study and high frequency digital circuit, signal processing and computer network and professional knowledge.
During the period of school attended many colleges in 2003, electronic manufacture competition with the &second compilation Delphi fiber welding machine, training simulation system& won the award outstanding graduate assistantships
1996. June 1999. To - - 19 it (Qingdao) from
Work experience:
&#6.04-2009.1
In XX communication R&D center in mobile phone radiofrequency hardware group of R&D project development and debugging, mainly responsible for rf circuit design and ...
for RF circuit design and debug, as a project team led by the excellent interface were A and B completed the task of CDMA R & D projects.
&#6.7-2005.10
In July 2003 after graduating from XX branch is responsible for the maintenance of BSC and MSC, the base station transmission割接and save the station. Can be used in accordance with the rate of channel carrier frequency to save, to see the quality of transmission line traffic monitoring, demolition LOAD data, road test data analysis, including access to the failure of the analysis of events such as dropped calls, network coverage of the assessment of the situation analysis, the propo...
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出门在外也不愁100分求配一双核电脑_百度知道
100分求配一双核电脑
最后兼容性要没问题啊:CPU,呵呵,显示器要个CRT就OK了:奔腾D 805主板:最好是华硕的要有独立显卡(起码要可以流畅运行HALF-LIFE2)由于资金有限以下是我的一些要求,我可不希望出现硬件冲突!其他就麻烦各位了
5200块可以配液晶了呢,那就帮我另配个吧,没1000那么夸张!另外奔腾D805大概是800块多了如果大家认为双核不是很成熟,拜托啦,价格还是,我要的就是游戏性能,P4或者AMD都可以啦
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当时看来其要求好高,只要看其支持的主板数量与类型就知道?小意思了~CPU 760 Intel Pentium D 805(盒装)
PD 820为 880元左右,考虑了游戏性,包括了CRT显示器,AMD的,确实需要400以上 .双核已经很成熟了,可以考虑下~主板 740 磐正 5P945I-Pro 或者华硕 P5LD2 SE
880(考虑一下前者!1年左右,天天涨价,当然越强越高~4500左右!一个平台的成熟,四核的都要出来了,ASUS低端缩水)内存 410 宇瞻 DDRII667 512MB
内存我无话可说,INTEL都可以,现在的配置玩那个,可以以后加根内存升级到1G硬盘 500 希捷 酷鱼7200!兼顾实际价格~~~预算范围内如你要求.9&#47!半条命2以前玩过
提问者评价
基本满足我的条件了,谢谢!
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双核电脑的相关知识
其他6条回答
玩游戏没多大问题.所以不建议.....买个AMD好一点的..现在双核不是太稳定..
不好办啊:光双核CPU都要1千左右的啊再加上光驱主版内存显卡机箱什么的5200还凑合
AMD3000+加1G内存加7600GS显卡
现在没必要买奔腾D 805 了,奔腾D 820更有性价比,
双核技术很成熟了,不用担心.下面是我推荐的配置.
配置类型:图像处理型 配置名称:11
配 置 人:ATfield 配置时间:2006
配件类别 产品名称 数量 当时价格 北京报价
CPU Intel 奔腾D 820 2.8GHz(散) 1 860.00 860.00
散热器: Tt 火星9(A.00 95.00
主板 华硕 P5LD2 SE 1 899.00 899.00
内存 黑金刚 512M DDRII667 2 325.00 325.00
硬盘 WD 鱼子酱 160G 7200转 8M(串口) 1 520.00 520.00
光驱 BenQ .00 170.00
显卡 华硕7600GT 1 999.00 999.00
机箱 世纪之星 D92D 1 140.00 140.00
电源 世纪之星 自由战士Ⅲ(直吹式) 1 170.00 170.00
CPU是奔腾D 820双核处理器,性能很强了,足够你用来...
这是最全的配置单了!希望你看完这些配置单后,能有很多收获,并能配置一台理想的电脑!!祝你成功!!
给你个intel配置
处理器: 赛扬D331(2.66G) 散 370元
风扇:酷冷 30元
内存: 宇瞻DDRII533/512M 310元
主板: 华硕 P5SD2-X 590元
硬盘:WD 鱼子酱JB 80G 8M(串口) 430元
显卡: 盈通7300GS 490元
键鼠: 双飞燕防水套装 50元
LCD: 冠捷AOC 171S+ 1850元
4000元INTEL家用经济配置
CPU Intel 赛扬 D 2.4G(散) 575.00
风扇 普通 20
主板 微星 865G Neo2-PLS 750.00
内存 威刚 256MB DDR 400 280.00
硬盘 WD 鱼子酱 80G 7200转 2M 465.00
康宝 三星 16X-DVD 390.00
机箱 技嘉 GC-505B1(3C电源) 290.00
音箱 A66B 188.00
键鼠套装 明基 键鼠套装之神雕侠侣 140.00
CRT显示器...
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