找人帮忙任务怎么做看一下怎么做谢谢

来源：蜘蛛抓取(WebSpider) 时间：2014-10-16 17:07 标签： 很快地看一下的词语
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/etc/nginx/nginx.conf.请老师帮我看一下这题怎么做，谢谢！(请写算式)&
欲语泪先流1682
这轮直径为0.8m，则轮的周长为πr=3.14×0.8=2.512m，每分钟跑200圈，则一分钟所走的路程为：2.512×200=502.4m，也就是说车的速度为：502.4m/min，那么通过的时间为总路程除以速度，即：=7.225≈7min.其实整个过程很简单，楼主你遇见问题首先想到的应该是自己去分析它，问题再复杂也是简单的问题的集合，不要总是依赖别人的...
圆的周长L=2nr,半径r=直径0.8：2=0.4米，L=2X0.4X3.14=2.512米
3630：（200X2.512）=7.2253所以大约要7分钟。
轮胎转一圈的长度是车轮的周长，算式为：3630/（0.8*3.14*200）=7.225分钟=7分钟（保留整数）
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